\(\overrightarrow{BA} . \overrightarrow{AC} = ||\overrightarrow{BA}|| \times ||\overrightarrow{AC}|| \times \cos(\overrightarrow{BA}, \overrightarrow{AC})\)
\(\overrightarrow{BA} . \overrightarrow{AC} = BA \times AC \times \cos(\pi - \widehat{BAC})\)
\(\overrightarrow{BA} . \overrightarrow{AC} = 5 \times 4 \times \cos\frac{2\pi}{3}\)
\(\overrightarrow{BA} . \overrightarrow{AC} = 20 \times (-\frac{1}{2}) = -10\)