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Trouver \(x\) tel que :

Question

a\(\frac{1}{x}=5\)

Solution

\(x=\frac{1}{5}=\frac{2}{10}=0,2\)

Question

b. \(\frac{1}{x}=-2\)

Solution

\(x=\frac{1}{-2}=\frac{-1}{2}=-0,5\)

Question

c.\(\frac{1}{x}=-0,5\)

Solution

\(x=\frac{1}{-0,5}=\frac{1}{\frac{-1}{2}}=\frac{2}{-1}=-2\)

Question

d.\(\frac{1}{x}=7\)\(\)

Solution

\(x=\frac{1}{7}\)

Question

e.\(\frac{1}{x}=0,4\)

Solution

\(x=\frac{1}{\frac{4}{10}}\)

\(x=\frac{10}{4}=2,5\)

Question

f.\(\frac{1}{x}=-4\)

Solution

\(x=\frac{1}{-4}=-0,25\)

Question

g.\(\frac{1}{x}=\frac{2}{3}\)

Solution

\(x=\frac{3}{2}=1,5\)

Question

h.\(\frac{2}{x}=-20\)

Solution

\(\frac{x}{2}=\frac{1}{-20}\)

\(x=\frac{1}{-20}\times 2\)

\(x=\frac{2}{-20}\)

\(x=\frac{-1}{10}=-0,1\)

Question

i.\(\frac{1}{5x}=0,1\)

Solution

\(5x=\frac{1}{0,1}\)

\(5x=\frac{1}{\frac{1}{10}}=10\)

\(x=2\)

Question

j.\(\frac{1}{x}=-1\)

Solution

\(x=\frac{1}{-1}=-1\)

Question

k.\(\frac{1}{x}=0\)

Solution

\(x=\frac{1}{0} \) \(\color{red}{\textbf{Il est impossible de diviser par 0 donc il n'y a pas de solution.}}\)